# Instructor’s Solutions Manual of College Algebra And by Richard N. Aufmann

By Richard N. Aufmann

Includes entire ideas to all odd-numbered difficulties within the textual content, in addition to learn advice and a tradition checks for every bankruptcy; textual content particular.

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Extra resources for Instructor’s Solutions Manual of College Algebra And Trigonometry

Sample text

3 + 2 −18)(2 + 2 −50) = (3 + 2i 18)(2 + 2i 50) = [3 + 2i (3 2 )][2 + 2i (5 2 )] = (3 + 6i 2 )(2 + 10i 2) = 3(2 + 10i 2 ) + 6i 2(2 + 10i 2 ) = 6 + 30i 2 + 12i 2 + 60i 2 ( 2)2 = 6 + 30i 2 + 12i 2 + 60( −1)(2) = 6 + 30i 2 + 12i 2 − 120 = (6 − 120) + (30i 2 + 12i 2 ) = −114 + 42i 2 36. (5 − 3 −48)(2 − 4 −27 ) = (5 − 3i 48)(2 − 4i 27 ) = [5 − 3i (4 3)][2 − 4i (3 3)] = (5 − 12i 3)(2 − 12i 3) = 5(2 − 12i 3) − 12i 3(2 − 12i 3) = 10 − 60i 3 − 24i 3 + 144i 2 ( 3) 2 = 10 − 60i 3 − 24i 3 + 144( −1)(3) = 10 − 60i 3 − 24i 3 − 432 = (10 − 432) + ( −60i 3 − 24i 3) = −422 − 84i 3 4 −8 = − 8 = −4 = −4 ⋅ i = −4i = −4i = 4i −1 2i 2i i i i i2 37.

Also note that y is the distance on level ground on the way to Jon’s house and on the way home. 5 minutes = 1 500 meters = a 2 km. rate Faster car x Slower car 80 0. 5 1 hour = hour. 60 120 time 1 120 1 120 distance x ⎛⎜ 1 ⎞⎟ − 80 ⎛⎜ 1 ⎞⎟ = 1 ⎝ 120 ⎠ ⎝ 120 ⎠ 2 x ⎡ ⎤ 120 ⎢ x ⎛⎜ 1 ⎞⎟ − 80 ⎛⎜ 1 ⎞⎟ ⎥ = 120 ⎛⎜ 1 ⎞⎟ 120 120 ⎝2⎠ ⎝ ⎠ ⎝ ⎠ ⎣ ⎦ x − 80 = 60 x = 140 140 km/h y z x y z x + y + z + x + y + z =1 4 6 12 12 6 4 y y ⎛ ⎞ 12 ⎜ x + + z + x + + z ⎟ = 12(1) ⎝ 4 6 12 12 6 4 ⎠ 3x + 2 y + z + x + 2 y + 3z = 12 4 x + 4 y + 4 z = 12 4( x + y + z ) = 12 x+ y+z=3 The distance to Jon’s house is 3 miles.

4] 16. 5] ⎜ ⎟⎜ ⎟ ⎜ ⎟ (5 − x )(5 + x ) ⎝ 5 − x ⎠⎝ x + 5 ⎠ x+5 ⎝ x + 5⎠ 25 − x 2 17. 5] − 2 2 = − = x + x − 6 x − 5 x + 6 ( x − 2)( x + 3) ( x − 2)( x − 3) ( x − 2)( x + 3) ( x − 3) 2 ( x − 6)( x + 1) x 2 − 5x − 6 = x − 3x − 2 x − 6 = = ( x − 2)( x + 3) ( x − 3) ( x − 2)( x + 3) ( x − 3) ( x − 2)( x + 3) ( x − 3) 18. 5] = 2 3 2 2 2 (2 x − 1)( x − 3) x ( x − 3) x −3 2x − 7x + 3 x − 3x x − 3x x − 3x 19. 5] a + b 2a − b a a + b a a (2a − b) 2a − b 2a − b a a ( 2a − b) 20. x− 21. 6] 23. 5] 2 2 2 x (2 x + 1) x (2 x − 1) 2 2 + 2 2 + − 2 2 − x x x x x x x x x = − = − = = = 2x + 1 2x + 1 2x + 1 2x + 1 2x + 1 2x + 1 2x + 1 22.